D

Step 1: Analyze the trajectories of projectiles A, B, and C.
Each projectile has a different angle of projection, which affects the time of flight, maximum height, and horizontal distance covered.
Step 2: Time of Flight
The time of flight for a projectile is given by the formula:
$$ T = \frac{2u \sin(\theta)}{g} $$
where $u$ is the launch speed, $\theta$ is the angle of projection, and $g$ is the acceleration due to gravity. Since projectiles A, B, and C have similar shapes in their trajectories (symmetric parabolas), it suggests that they may have the same time of flight.
Step 3: Launch Speed
Particle C appears to reach the highest vertical point among the three, which indicates that it has the highest launch speed since a larger vertical component contributes to a greater height. Therefore, the launch speed for particle C is greatest.
Step 4: Horizontal Velocity Component
The horizontal component of velocity is independent of the vertical motion and is given by $$ v_x = u \cos(\theta) $$ where $\theta$ is the angle of projection. Given that particle C has a higher launch speed, it likely has the greatest horizontal component as well. Thus, each of the statements in the options is true.
Conclusion:
Since all options A, B, and C are true, the answer is D: All of the above.